Sodium oxalate on heating with conc. $H_2SO_4$ gives

  • A
    $CO$ only
  • B
    $CO_2$ only
  • C
    $CO$ and $CO_2$
  • D
    $SO_2$ and $SO_3$

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Similar Questions

$CuSO_4$ solution $+$ lime is called

Match Column-$I$ with Column-$II$ for the given properties/applications mentioned therein.
Column-$I$ Column-$II$
$A$. $H$ $1$. Used in the name of perhydrol.
$B$. $H_2$ $2$. Can be reduced to dihydrogen by $NaH$.
$C$. $H_2O$ $3$. Can be used in hydroformylation of olefin.
$D$. $H_2O_2$ $4$. Can be used in cutting and welding.

Correct order of boiling point $(BP)$ is:

In which of the following reactions,$H_2$ is liberated?
$i$. $Al_{(s)} + HCl_{(aq)} \rightarrow$
$ii$. $Al_{(s)} + NaOH_{(aq)} \rightarrow$
$iii$. $B_2H_{6(g)} + H_2O_{(l)} \rightarrow$
$iv$. $F_{2(g)} + H_2O_{(l)} \rightarrow$

Match the following and identify the correct option.
$a. CO_{(g)} + H_{2(g)}$ $i. Mg(HCO_3)_2 + Ca(HCO_3)_2$
$b. \text{Temporary hardness of water}$ $ii. \text{An electron deficient hydride}$
$c. B_2H_6$ $iii. \text{Synthesis gas}$
$d. H_2O_2$ $iv. \text{Non-planar structure}$

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