$CuSO_4$ solution $+$ lime is called

Sodium oxalate on heating with conc. $H_2SO_4$ gives

Match the terms in Column $-I$ with the relevant item in Column $-II$.

Column $-I$	Column $-II$
$A$. Electrolysis of water produces	$1$. atomic reactor
$B$. Lithium aluminium hydride is used as	$2$. polar molecule
$C$. Hydrogen chloride is a	$3$. recombines on metal surface to generate high temperature
$D$. Heavy water is used in	$4$. reducing agent
$E$. Atomic hydrogen	$5$. hydrogen and oxygen

Match the following and identify the correct option.

$a. CO_{(g)} + H_{2(g)}$	$i. Mg(HCO_3)_2 + Ca(HCO_3)_2$
$b. \text{Temporary hardness of water}$	$ii. \text{An electron deficient hydride}$
$c. B_2H_6$	$iii. \text{Synthesis gas}$
$d. H_2O_2$	$iv. \text{Non-planar structure}$

List-$I$ contains compounds and List-$II$ contains reactions.

List-$I$	List-$II$
$I$. $H_2O_2$	$P$. $Mg(HCO_3)_2 + Ca(OH)_2 \rightarrow$
$II$. $Mg(OH)_2$	$Q$. $BaO_2 + H_2SO_4 \rightarrow$
$III$. $BaCl_2$	$R$. $Ca(OH)_2 + MgCl_2 \rightarrow$
$IV$. $CaCO_3$	$S$. $BaO_2 + HCl \rightarrow$
	$T$. $Ca(HCO_3)_2 + Ca(OH)_2 \rightarrow$

Match each compound in List-$I$ with its formation reaction$(s)$ in List-$II$,and choose the correct option.

Consider the following statements:
$I$. Atomic hydrogen is obtained by passing an electric arc through hydrogen gas.
$II$. Hydrogen gas does not reduce heated aluminum oxide.
$III$. Finely divided palladium absorbs a large volume of hydrogen gas.
$IV$. Pure nascent hydrogen is obtained by the reaction of $Na$ with $C_2H_5OH$.
Which of the above statements are correct?