The size of the nucleus is of the order of:

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(B) The radius of a nucleus is given by the formula $R = R_0 A^{1/3}$, where $R_0$ is a constant approximately equal to $1.2 	imes 10^{-15} \ m$ to $

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$10^{-15} \ m$

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(B) The radius of a nucleus is given by the formula $R = R_0 A^{1/3}$, where $R_0$ is a constant approximately equal to $1.2 	imes 10^{-15} \ m$ to $1.5 	imes 10^{-15} \ m$ and $A$ is the mass number.Since the mass number $A$ typically ranges from $1$ to $238$, the value of $A^{1/3}$ is of the order of $1$ to $6$.Therefore, the size of the nucleus is primarily determined by the order of $R_0$, which is $10^{-15} \ m$ (also known as $1 \ 	ext{fermi}$ or $1 \ 	ext{fm}$).Thus, the correct order of magnitude for the size of the nucleus is $10^{-15} \ m$.

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