Six wires,each of cross-sectional area $A$ and length $l$,are combined as shown in the figure. The thermal conductivities of copper and iron are $K_1$ and $K_2$ respectively. The equivalent thermal resistance between points $A$ and $C$ is:

  • A
    $\frac{l(K_1+K_2)}{K_1K_2A}$
  • B
    $\frac{2l(K_1+K_2)}{K_1K_2A}$
  • C
    $\frac{l}{(K_1+K_2)A}$
  • D
    $\frac{2l}{(K_1+K_2)A}$

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