Simplify the following:frac{3}{sqrt{8}} + fra | vedclass

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(B) Given expression: $\frac{3}{\sqrt{8}} + \frac{1}{\sqrt{2}}$First,simplify $\sqrt{8}$ as $\sqrt{4 	imes 2} = 2\sqrt{2}$.Substitute this into the e

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$\frac{5 \sqrt{2}}{4}$

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(B) Given expression: $\frac{3}{\sqrt{8}} + \frac{1}{\sqrt{2}}$First,simplify $\sqrt{8}$ as $\sqrt{4 	imes 2} = 2\sqrt{2}$.Substitute this into the expression: $\frac{3}{2\sqrt{2}} + \frac{1}{\sqrt{2}}$.To add these fractions,find a common denominator,which is $2\sqrt{2}$.$\frac{3}{2\sqrt{2}} + \frac{1 	imes 2}{\sqrt{2} 	imes 2} = \frac{3}{2\sqrt{2}} + \frac{2}{2\sqrt{2}}$.$= \frac{3 + 2}{2\sqrt{2}} = \frac{5}{2\sqrt{2}}$.Rationalize the denominator by multiplying the numerator and denominator by $\sqrt{2}$:$= \frac{5 	imes \sqrt{2}}{2\sqrt{2} 	imes \sqrt{2}} = \frac{5\sqrt{2}}{2 	imes 2} = \frac{5\sqrt{2}}{4}$.

Simplify the following:
$\frac{3}{\sqrt{8}} + \frac{1}{\sqrt{2}}$

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Simplify the following:$\frac{3}{\sqrt{8}} + \frac{1}{\sqrt{2}}$