Simplify $\frac{(0.9743)^{3}-(0.0257)^{3}}{(0.9743)^{2}+(0.9743)(0.0257)+(0.0257)^{2}}$

Three numbers are in the ratio $4: 5: 6$ and their average is $25$. The largest number is

$A$ number when divided by $361$ gives a remainder $47$. If the same number is divided by $19$,the remainder obtained is

If the number $481*673$ is completely divisible by $9$,then the smallest whole number in place of $*$ will be

$5.6 \times 12.5 \div 0.5 + 15.5 = ? + 49.5$

$\left[ {10 + \left\{ {4 \times \left( {\overline {\frac{2}{3} + \frac{1}{4}} \times \sqrt {\frac{{144}}{{121}}} + 23} \right) \div 12 + 5} \right\} - 3} \right] = ?$