A number when divided by 361 gives a remainde | vedclass

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Question

(B) Let the number be $N$. According to the problem,$N = 361q + 47$,where $q$ is the quotient.We can rewrite $361$ as $19 	imes 19$. So,$N = 19(19q)

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(B) Let the number be $N$. According to the problem,$N = 361q + 47$,where $q$ is the quotient.We can rewrite $361$ as $19 	imes 19$. So,$N = 19(19q) + 47$.To find the remainder when $N$ is divided by $19$,we divide the expression by $19$.The term $19(19q)$ is perfectly divisible by $19$.Thus,the remainder depends on dividing $47$ by $19$.$47 = 19 	imes 2 + 9$.The remainder is $9$.

$A$ number when divided by $361$ gives a remainder $47$. If the same number is divided by $19$,the remainder obtained is

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