Select the molecule in which all the atoms ma | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For all atoms to lie in a single plane,all carbon atoms and the atoms attached to the benzene ring must be $sp^2$ hybridized to maintain planarity

Vedclass · Accepted Answer

$4-$Nitrobenzaldehyde

Vedclass · Answer

(A) For all atoms to lie in a single plane,all carbon atoms and the atoms attached to the benzene ring must be $sp^2$ hybridized to maintain planarity through conjugation.In $4-$Nitrobenzaldehyde $(O_2N-C_6H_4-CHO)$,the benzene ring,the nitro group $(-NO_2)$,and the aldehyde group $(-CHO)$ are all $sp^2$ hybridized.The conjugation extends throughout the molecule,allowing all atoms (including the hydrogen of the aldehyde group) to lie in the same plane.In other options,groups like $-OCH_3$ (in $4-$Methoxybenzaldehyde),$-CH_3$ (in $4-$Methylnitrobenzene),and $-COCH_3$ (in $4-$Nitroacetophenone) contain $sp^3$ hybridized carbon atoms,which possess tetrahedral geometry and prevent all atoms from lying in a single plane.

Select the molecule in which all the atoms may lie on a single plane.

Similar Questions

What is the type of hybridization of $Xe$ in $XeF_2$?

Consider the following reaction: $MX_4 + X'_2 \to MX_4X'_2$. If the atomic number of $M$ is $52$ and $X$ and $X'$ are halogens and $X'$ is more electronegative than $X$. Then choose the correct statement regarding the given information.

In methane,the bond angle is $......^o$.

In which of the following species,$d$-orbitals having $xz$ and $yz$ two nodal planes involved in hybridization of central atom?

As compared to pure atomic orbitals,hybrid orbitals have

Vedclass Test Series

Exam Paper Generator

Online Exam Module