What is the type of hybridization of Xe in Xe | vedclass

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(C) The total number of valence electrons in $XeF_2$ is $8 + (2 	imes 7) = 22$. To find the hybridization,we calculate the steric number $(X)$: $X =

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$sp^3d$

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(C) The total number of valence electrons in $XeF_2$ is $8 + (2 	imes 7) = 22$. To find the hybridization,we calculate the steric number $(X)$: $X = \frac{1}{2} [V + M - C + A]$,where $V$ is the number of valence electrons of the central atom,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge. For $XeF_2$: $V = 8$,$M = 2$,$C = 0$,$A = 0$. $X = \frac{1}{2} [8 + 2] = 5$. $A$ steric number of $5$ corresponds to $sp^3d$ hybridization.

List-$I$	List-$II$
$(1)$ Tetrahedral	$(A)$ $sp^2$
$(2)$ Trigonal planar	$(B)$ $sp$
$(3)$ Linear	$(C)$ $sp^3$

What is the type of hybridization of $Xe$ in $XeF_2$?

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