Select the correct order:(a) CO

Question

(B) For $(a)$: Bond length is inversely proportional to bond order. Bond orders are $CO (3)$,$CO_2 (2)$,$CO_3^{2-} (1.33)$. Thus,the bond length order

Vedclass · Accepted Answer

only $(a), (b)$

Vedclass · Answer

(B) For $(a)$: Bond length is inversely proportional to bond order. Bond orders are $CO (3)$,$CO_2 (2)$,$CO_3^{2-} (1.33)$. Thus,the bond length order $CO For $(b)$: Bond orders are $O_2 (2)$,$O_3 (1.5)$,$O_2^{2-} (1)$. Thus,the bond length order $O_2 For $(c)$: Bond energy is directly proportional to bond order. Bond order of $N_2$ is $3$ and $N_2^+$ is $2.5$. Thus,$N_2 > N_2^+$. The given order $N_2 Therefore,only $(a)$ and $(b)$ are correct.

Select the correct order:
$(a)$ $CO < CO_2 < CO_3^{2-}$ $\Rightarrow$ Bond length
$(b)$ $O_2 < O_3 < O_2^{2-}$ $\Rightarrow$ Bond length
$(c)$ $N_2 < N_2^+$ $\Rightarrow$ Bond energy

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Select the correct order:$(a)$ $CO < CO_2 < CO_3^{2-}$ $\Rightarrow$ Bond length$(b)$ $O_2 < O_3 < O_2^{2-}$ $\Rightarrow$ Bond length$(c)$ $N_2 < N_2^+$ $\Rightarrow$ Bond energy