Which of the following orders is CORRECT? | vedclass

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(A) $1$. $B(OH)_3$ has intermolecular hydrogen bonding,leading to a higher boiling point than $B(OMe)_3$. Thus,$B(OH)_3 > B(OMe)_3$ is correct.$2$. Ba

Vedclass · Accepted Answer

$B(OH)_3 > B(OMe)_3 \rightarrow$ Boiling point

Vedclass · Answer

(A) $1$. $B(OH)_3$ has intermolecular hydrogen bonding,leading to a higher boiling point than $B(OMe)_3$. Thus,$B(OH)_3 > B(OMe)_3$ is correct.$2$. Basic strength order is $NaH > NaNH_2 > NaOH$ because $H^-$ is a stronger base than $NH_2^-$,which is stronger than $OH^-$.$3$. Bond energy order for halogens is $Cl_2 > Br_2 > F_2 > I_2$. $F_2$ has low bond energy due to inter-electronic repulsion.$4$. Stability of trihalide ions is $I_3^- > Br_3^- > Cl_3^-$,as larger atoms stabilize the negative charge better.

Which of the following orders is $CORRECT$?

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