The same current is flowing in two alternatin | vedclass

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(D) For the first circuit (inductor only),the current is given by $i = \frac{V}{X_L} = \frac{V}{\omega L} = \frac{V}{2\pi f L}$.As the frequency $f$ i

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Decreases in the first circuit and increases in the other

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(D) For the first circuit (inductor only),the current is given by $i = \frac{V}{X_L} = \frac{V}{\omega L} = \frac{V}{2\pi f L}$.As the frequency $f$ increases,the inductive reactance $X_L = 2\pi f L$ increases,which causes the current $i$ to decrease.For the second circuit (capacitor only),the current is given by $i = \frac{V}{X_C} = V\omega C = V(2\pi f)C$.As the frequency $f$ increases,the capacitive reactance $X_C = \frac{1}{2\pi f C}$ decreases,which causes the current $i$ to increase.Therefore,the current decreases in the first circuit and increases in the second circuit.

Column-$I$	Column-$II$
$(a)$ Parturition	$(p)$ Attachment of embryo to endometrium
$(b)$ Gestation	$(q)$ Release of egg from Graafian follicle
$(c)$ Ovulation	$(r)$ Delivery of Foetus from uterus
$(d)$ Implantation	$(s)$ Duration between pregnancy and birth
	$(t)$ Formation of zygote by fusion of egg and sperm

The same current is flowing in two alternating circuits. The first circuit contains only an inductor and the second contains only a capacitor. If the frequency of the $e.m.f.$ of the $ac$ source is increased,what will be the effect on the value of the current in these circuits?

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