If vec{P} cdot vec{Q} = PQ,then the angle bet | vedclass

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(A) The dot product of two vectors $\vec{P}$ and $\vec{Q}$ is defined as $\vec{P} \cdot \vec{Q} = PQ \cos 	heta$,where $	heta$ is the angle between

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(A) The dot product of two vectors $\vec{P}$ and $\vec{Q}$ is defined as $\vec{P} \cdot \vec{Q} = PQ \cos 	heta$,where $	heta$ is the angle between the vectors.Given that $\vec{P} \cdot \vec{Q} = PQ$.Substituting this into the formula: $PQ = PQ \cos 	heta$.Dividing both sides by $PQ$ (assuming $P, Q 
eq 0$),we get $\cos 	heta = 1$.Since $\cos 0^\circ = 1$,the angle $	heta = 0^\circ$.

If $\vec{P} \cdot \vec{Q} = PQ$,then the angle between $\vec{P}$ and $\vec{Q}$ is ............. $^\circ$.

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