The resolving power of an electron microscope | vedclass

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(C) The resolving power of a microscope is inversely proportional to the wavelength of the radiation used,given by the relation $RP \propto \frac{1}{\

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The wavelength of an electron is much smaller than the wavelength of visible light

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(C) The resolving power of a microscope is inversely proportional to the wavelength of the radiation used,given by the relation $RP \propto \frac{1}{\lambda}$.Visible light has a wavelength in the range of $4000 \, \mathring{A}$ to $7000 \, \mathring{A}$.According to the de Broglie hypothesis,the wavelength of an electron is given by $\lambda = \frac{h}{p} = \frac{h}{\sqrt{2mE}}$.For an electron accelerated through a potential difference $V$,the wavelength is approximately $\lambda \approx \frac{12.27}{\sqrt{V}} \, \mathring{A}$.Even for a small accelerating voltage,the wavelength of an electron is significantly smaller than the wavelength of visible light.Since $\lambda_{	ext{electron}} < \lambda_{	ext{light}}$,the resolving power of an electron microscope is much higher than that of an optical microscope.

The resolving power of an electron microscope is greater than the resolving power of an optical microscope because

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