Reduction of the metal centre in aqueous perm | vedclass

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Question

(A) In neutral medium:$MnO_4^- + 2H_2O + 3e^- \rightarrow MnO_2 + 4OH^-$(Involves $3$ electrons)In alkaline medium:$MnO_4^- + e^- \rightarrow MnO_4^{2

Vedclass · Accepted Answer

$A, C, D$

Vedclass · Answer

(A) In neutral medium:$MnO_4^- + 2H_2O + 3e^- \rightarrow MnO_2 + 4OH^-$(Involves $3$ electrons)In alkaline medium:$MnO_4^- + e^- \rightarrow MnO_4^{2-}$$MnO_4^{2-} + 2H_2O + 2e^- \rightarrow MnO_2 + 4OH^-$Overall: $MnO_4^- + 2H_2O + 3e^- \rightarrow MnO_2 + 4OH^-$(Involves $3$ electrons)In acidic medium:$MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O$(Involves $5$ electrons)Comparing with the options:$A$: $3$ electrons in neutral medium (Correct)$B$: $5$ electrons in neutral medium (Incorrect)$C$: $3$ electrons in alkaline medium (Correct)$D$: $5$ electrons in acidic medium (Correct)Thus,the correct combination is $A, C, D$.

List-$I$ (Types of redox reactions)	List-$II$ (Examples)
$a.$ Combination reaction	$(i)$ $Cl_{2(g)} + 2Br^-_{(aq)} \rightarrow 2Cl^-_{(aq)} + Br_{2(l)}$
$b.$ Decomposition reaction	$(ii)$ $2H_2O_{2(aq)} \rightarrow 2H_2O_{(l)} + O_{2(g)}$
$c.$ Displacement reaction	$(iii)$ $CH_{4(g)} + 2O_{2(g)} \xrightarrow{\Delta} CO_{2(g)} + 2H_2O_{(l)}$
$d.$ Disproportionation reaction	$(iv)$ $2H_2O_{(l)} \xrightarrow{\text{electrolysis}} 2H_{2(g)} + O_{2(g)}$

Reduction of the metal centre in aqueous permanganate ion involves

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