Product (B) in this reaction is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction proceeds in two steps:$1$. Aniline reacts with bromine water $(Br_2/H_2O)$ to form $2,4,6$-tribromoaniline as product $(A)$ due to th

Vedclass · Accepted Answer

$1,3,5-$tribromobenzene

Vedclass · Answer

(B) The reaction proceeds in two steps:$1$. Aniline reacts with bromine water $(Br_2/H_2O)$ to form $2,4,6$-tribromoaniline as product $(A)$ due to the strong activating effect of the $-NH_2$ group.$2$. $2,4,6$-tribromoaniline is then treated with $NaNO_2/HCl$ at $0-5 \ ^\circ C$ to form the diazonium salt,which is subsequently reduced by $H_3PO_2$ and $H_2O$ to remove the $-NH_2$ group,yielding $1,3,5$-tribromobenzene as product $(B)$.

Product $(B)$ in this reaction is

Similar Questions

Acetanilide can be prepared from aniline and which of the following?

Identify the major product formed in the following reaction: $C_6H_5NH_2 + CHCl_3 + 3KOH \to ?$

Treatment of ammonia with excess of ethyl chloride will yield

When chloroform is treated with a primary amine and $KOH$,what is the characteristic smell of the product formed?

The reaction given below is known as:
$ArN_2^+ X^- + Cu_2Cl_2 + HCl \to ArCl + N_2 + Cu_2Cl_2$

Vedclass Test Series

Exam Paper Generator

Online Exam Module