The readings of ammeters A_1, A_2 and A_3 wil | vedclass

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(C) Let the potential of the common junction be $V$. Applying Kirchhoff's Current Law $(KCL)$ at the junction:$\frac{V-10}{6} + \frac{V-4}{8} + \frac{

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$1\,A, 0.5\,A, 0.5\,A$

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(C) Let the potential of the common junction be $V$. Applying Kirchhoff's Current Law $(KCL)$ at the junction:$\frac{V-10}{6} + \frac{V-4}{8} + \frac{V-0}{0} = 0$ (assuming ideal ammeters with zero resistance).Alternatively,using nodal analysis as shown in the image,the potential at the junction is $4\,V$.$1$. Current through $A_1$ (flowing from $10\,V$ to $4\,V$ through $6\,\Omega$): $I_1 = \frac{10-4}{6} = 1\,A$.$2$. Current through $A_3$ (flowing from $4\,V$ to $0\,V$ through $8\,\Omega$): $I_3 = \frac{4-0}{8} = 0.5\,A$.$3$. Applying $KCL$ at the junction: $I_1 = I_2 + I_3$,where $I_2$ is the current through $A_2$.$1\,A = I_2 + 0.5\,A \implies I_2 = 0.5\,A$.Thus,the readings are $A_1 = 1\,A, A_2 = 0.5\,A, A_3 = 0.5\,A$.

The readings of ammeters $A_1, A_2$ and $A_3$ will be respectively:

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