Potential difference between A and B is ..... | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The circuit represents a balanced Wheatstone bridge configuration.In a balanced Wheatstone bridge,the ratio of resistances in opposite arms is equ

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(D) The circuit represents a balanced Wheatstone bridge configuration.In a balanced Wheatstone bridge,the ratio of resistances in opposite arms is equal,which means no current flows through the central galvanometer or resistor connected between points $A$ and $B$.Since no current flows through the branch between $A$ and $B$,the potential at point $A$ is equal to the potential at point $B$.Therefore,the potential difference $V_B - V_A = 0 \ V$.

Potential difference between $A$ and $B$ is .............. $V$.

Similar Questions

Kirchhoff's first law,$i.e.$,$\Sigma i = 0$ at a junction,is based on the law of conservation of:

The figure below shows a portion of an electric circuit with the currents in amperes and their directions. The magnitude and direction of the current in the portion $PQ$ is

In the arrangement of resistors shown in the diagram,the potential difference between $B$ and $D$ will be zero when the unknown resistance $X$ is ............... $\Omega$.

If the resistances are chosen for the circuit shown in the figure in such a way that no current flows through the battery with emf $E_1 = 2 \ V$,the voltage $V_2$ across $R_2$ and the current $I_3$ flowing through $R_3$ are respectively,

The current $I$ in the circuit shown is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module