Reaction of isobutylene with concentrated $H_2SO_4 + SO_3$ (oleum) gives:

  • A
    $2-$Methylpropane$-2-$sulphonic acid
  • B
    $t-$Butylsulphonic acid
  • C
    Both
  • D
    None

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$HCl$ does not show the peroxide effect because the reaction mechanism involves the following steps:
$CH_3-CH=CH_2 + \dot{X} \to CH_3-\dot{C}H-CH_2X$ $(I)$
$CH_3-\dot{C}H-CH_2X + HX \to CH_3-CH_2-CH_2X + \dot{X}$ $(II)$
Why does $HCl$ fail to undergo this reaction?

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$Ph-CH=CH_2 \xrightarrow[HBr]{(PhCOO)_2} \text{Product}$
Consider the above reaction:
$A$. The reaction proceeds through a more stable radical intermediate.
$B$. The role of peroxide is to generate $\dot{H}$ (Hydrogen radical).
$C$. During this reaction,benzene is formed as a byproduct.
$D$. $1-\text{Bromo}-2-\text{phenylethane}$ is formed as the minor product.
$E$. The same reaction in the absence of peroxide proceeds via a carbocation intermediate.
Identify the correct statements. Choose the correct answer from the options given below:

Find out the $X$ of the given reaction :-

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Write the $IUPAC$ names of the products obtained by the addition reaction of $HBr$ to $hex-1-ene$:
$(i)$ in the absence of peroxide and
$(ii)$ in the presence of peroxide.

In the reaction $C_2H_5CH = CH_2 + H - X \rightarrow$ Product,what is the major product?

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