Reaction of aqueous sodium hydroxide on (i) e | vedclass

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(C) $(i)$ Ethyl bromide reacts with aqueous $NaOH$ via nucleophilic substitution to form ethyl alcohol:$C_2H_5Br + NaOH_{(aq)} 	o C_2H_5OH + NaBr$$(i

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$(i)$ Ethyl alcohol and $(ii)$ phenol

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(C) $(i)$ Ethyl bromide reacts with aqueous $NaOH$ via nucleophilic substitution to form ethyl alcohol:$C_2H_5Br + NaOH_{(aq)} 	o C_2H_5OH + NaBr$$(ii)$ Chlorobenzene is resistant to nucleophilic substitution under normal conditions due to resonance and $sp^2$ hybridized carbon. However,under drastic conditions $(623 \ K, 300 \ atm)$,it reacts with aqueous $NaOH$ to form sodium phenoxide,which upon acidification gives phenol:$C_6H_5Cl + 2NaOH_{(aq)} \xrightarrow{623 \ K, 300 \ atm} C_6H_5ONa + NaCl + H_2O$$C_6H_5ONa + HCl 	o C_6H_5OH + NaCl$

Reaction of aqueous sodium hydroxide on $(i)$ ethyl bromide and $(ii)$ chlorobenzene gives

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