Reaction of BeO with ammonia and hydrogen flu | vedclass

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Question

(A) The reaction of beryllium oxide $(BeO)$ with ammonia $(NH_3)$ and hydrogen fluoride $(HF)$ is a standard method for the preparation of ammonium te

Vedclass · Accepted Answer

$(NH_4)_2BeF_4$

Vedclass · Answer

(A) The reaction of beryllium oxide $(BeO)$ with ammonia $(NH_3)$ and hydrogen fluoride $(HF)$ is a standard method for the preparation of ammonium tetrafluoroberyllate.The balanced chemical equation is: $BeO + 2 NH_3 + 4 HF \rightarrow (NH_4)_2BeF_4 + H_2O$.Upon thermal decomposition,$(NH_4)_2BeF_4$ breaks down into beryllium fluoride $(BeF_2)$ and ammonium fluoride $(NH_4F)$: $(NH_4)_2BeF_4 \xrightarrow{\Delta} BeF_2 + 2 NH_4F$.Therefore,'$A$' is $(NH_4)_2BeF_4$.

Reaction of $BeO$ with ammonia and hydrogen fluoride gives '$A$' which on thermal decomposition gives $BeF_2$ and $NH_4F$. What is '$A$'?

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