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(C) The reaction is a Friedel-Crafts alkylation involving the ring-opening of a cyclic ether. The reactant $(A)$ is $2,2,5,5$-tetramethyltetrahydrofur

Vedclass · Accepted Answer

$2,2,5,5-$tetramethyltetrahydrofuran

Vedclass · Answer

(C) The reaction is a Friedel-Crafts alkylation involving the ring-opening of a cyclic ether. The reactant $(A)$ is $2,2,5,5$-tetramethyltetrahydrofuran. In the presence of an acid catalyst $(H_2SO_4)$,the cyclic ether undergoes protonation followed by ring opening to form a carbocation,which then undergoes electrophilic aromatic substitution with benzene to form the final product.

Reactant $(A)$ is:

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