'A' and 'B' formed in the following set of re | vedclass

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Question

(A) In the first reaction,$3-	ext{hydroxybenzyl alcohol}$ reacts with $HBr$. The benzylic $-OH$ group is more reactive towards substitution than the

Vedclass · Accepted Answer

$A = 	ext{3-hydroxybenzyl bromide}, B = 	ext{resorcinol}$

Vedclass · Answer

(A) In the first reaction,$3-	ext{hydroxybenzyl alcohol}$ reacts with $HBr$. The benzylic $-OH$ group is more reactive towards substitution than the phenolic $-OH$ group. Thus,the benzylic $-OH$ is replaced by $-Br$ to form $3-	ext{hydroxybenzyl bromide}$ $(A)$.In the second reaction,$3-	ext{methoxyphenol}$ reacts with $HBr$ under heating. $HBr$ cleaves the ether linkage $(-OCH_3)$ to form a phenol and methyl bromide. The phenolic $-OH$ group remains intact. Thus,the product $B$ is resorcinol $(1,3-	ext{dihydroxybenzene})$.

$'A'$ and $'B'$ formed in the following set of reactions are :

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