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(B) To rationalise the denominator of $\frac{3+\sqrt{2}}{4 \sqrt{2}}$,we multiply both the numerator and the denominator by $\sqrt{2}$:$\frac{3+\sqrt{

Vedclass · Accepted Answer

$\frac{3 \sqrt{2}+2}{8}$

Vedclass · Answer

(B) To rationalise the denominator of $\frac{3+\sqrt{2}}{4 \sqrt{2}}$,we multiply both the numerator and the denominator by $\sqrt{2}$:$\frac{3+\sqrt{2}}{4 \sqrt{2}} = \frac{3+\sqrt{2}}{4 \sqrt{2}} 	imes \frac{\sqrt{2}}{\sqrt{2}}$$= \frac{\sqrt{2}(3+\sqrt{2})}{4 	imes (\sqrt{2} 	imes \sqrt{2})}$$= \frac{3 \sqrt{2} + 2}{4 	imes 2}$$= \frac{3 \sqrt{2} + 2}{8}$

Rationalise the denominator of the following:
$\frac{3+\sqrt{2}}{4 \sqrt{2}}$

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Rationalise the denominator of the following:$\frac{3+\sqrt{2}}{4 \sqrt{2}}$