(A) The initial rate is given by $r_1 = k[A]^a[B]^b$. When the concentration of $A$ is doubled $([A]' = 2[A])$ and $B$ is halved $([B]' = \frac{1}{2}[

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) The initial rate is given by $r_1 = k[A]^a[B]^b$. When the concentration of $A$ is doubled $([A]' = 2[A])$ and $B$ is halved $([B]' = \frac{1}{2}[B])$,the new rate $r_2$ is: $r_2 = k(2[A])^a(\frac{1}{2}[B])^b$ $r_2 = k \cdot 2^a \cdot [A]^a \cdot (2^{-1})^b \cdot [B]^b$ $r_2 = 2^a \cdot 2^{-b} \cdot k[A]^a[B]^b$ $r_2 = 2^{a-b} \cdot r_1$ Therefore,the ratio $\frac{r_2}{r_1} = 2^{a-b}$.

Class 12 Chemistry Chemical Kinetics Rate law , Rate constant , Order of Reaction and Molecularity

Medium

Rate of reaction is $r_1 = k[A]^a[B]^b$. If the concentration of $A$ is doubled and $B$ is halved,the new rate is $r_2$. What is the value of $\frac{r_2}{r_1}$?

MHT CET 2025 All MHT CET

A
$2^{a-b}$
B
$2^{a+b}$
C
$2^{b-a}$
D
$2^{-(a+b)}$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Chemical Kinetics

Subtopic

Rate law , Rate constant , Order of Reaction and Molecularity

Previous Year

MHT CET 2025 Paper All MHT CET years →

Assertion: The order of a reaction can have a fractional value.
Reason: The order of a reaction cannot be determined from the balanced chemical equation of a reaction.

MediumAIIMS 2008

View Solution

Rate of reaction is given by the following rate law $-\frac{d[C]}{dt} = \frac{k_1 [C]}{1 + k_2 [C]}$. Determine the order of reaction when the concentration $[C]$ is very high.

Medium

View Solution

Write the unit of the rate constant for the following reactions:
$1.$ Zero order
$2.$ Second order

Medium

View Solution

For a reaction: $3X \to 4Y$,calculate the rate of reaction based on the following graph when the concentration of $X$ is $0.1 \ M$.

Difficult

View Solution

For the reaction $X + Y \rightarrow Z$,the rate law is $r = K[X][Y]$. If the concentration of $Y$ is increased significantly,what will be the order of the reaction?

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Rate of reaction is $r_1 = k[A]^a[B]^b$. If the concentration of $A$ is doubled and $B$ is halved,the new rate is $r_2$. What is the value of $\frac{r_2}{r_1}$?

Similar Questions

Assertion: The order of a reaction can have a fractional value.Reason: The order of a reaction cannot be determined from the balanced chemical equation of a reaction.

Rate of reaction is given by the following rate law $-\frac{d[C]}{dt} = \frac{k_1 [C]}{1 + k_2 [C]}$. Determine the order of reaction when the concentration $[C]$ is very high.

Write the unit of the rate constant for the following reactions:$1.$ Zero order$2.$ Second order

For a reaction: $3X \to 4Y$,calculate the rate of reaction based on the following graph when the concentration of $X$ is $0.1 \ M$.

For the reaction $X + Y \rightarrow Z$,the rate law is $r = K[X][Y]$. If the concentration of $Y$ is increased significantly,what will be the order of the reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Assertion: The order of a reaction can have a fractional value.
Reason: The order of a reaction cannot be determined from the balanced chemical equation of a reaction.

Write the unit of the rate constant for the following reactions:
$1.$ Zero order
$2.$ Second order