Rank the hydrogen atoms (H_a, H_b, H_c) in th | vedclass

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(C) The acidic strength of hydrogen atoms depends on the stability of the conjugate base (carbanion) formed after the removal of the proton. Removing

Vedclass · Accepted Answer

$b > c > a$

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(C) The acidic strength of hydrogen atoms depends on the stability of the conjugate base (carbanion) formed after the removal of the proton. Removing $H_a$ creates a carbanion at the $sp^3$ carbon. Removing $H_b$ creates a carbanion at the $sp^3$ carbon adjacent to the double bond (allylic position),which is stabilized by resonance. Removing $H_c$ creates a carbanion at the $sp^2$ carbon of the double bond (vinylic position). The stability order of the resulting anions is: Allylic carbanion $>$ Vinylic carbanion $>$ Alkyl carbanion. Therefore,the acidic strength order is $H_b > H_c > H_a$.

Rank the hydrogen atoms $(H_a, H_b, H_c)$ in the following molecule according to their acidic strengths.

Similar Questions

Given below are two statements:
Statement $I$: On the basis of inductive effect,the order of stability of alkyl carbanions is $CH_3^- > CH_3CH_2^- > (CH_3)_2CH^- > (CH_3)_3C^-$.
Statement $II$: Allyl and benzyl carbanions are more stabilised by inductive effect and not by resonance effect.

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What is the difference between inductive effect and resonance effect?

In the following resonance structures,the curved arrow indicates that electrons are shifted from:

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