Range of a bob of mass 1, kg is 80,m while it | vedclass

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Question

$H=\frac{1}{2} g\left(\frac{T}{2}ight)^{2}$

$20=\frac{1}{2} 	imes 10\left(\frac{\mathrm{T}}{2}ight)^{2}$

$\mathrm{T}=4$ second

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Vedclass · Accepted Answer

$40$

Vedclass · Answer

$H=\frac{1}{2} g\left(\frac{T}{2}ight)^{2}$

$20=\frac{1}{2} 	imes 10\left(\frac{\mathrm{T}}{2}ight)^{2}$

$\mathrm{T}=4$ second

Change in momentum $\overrightarrow{\Delta \mathrm{P}}=\overrightarrow{\mathrm{F}} . \Delta \mathrm{t}$

$=\mathrm{mg} \Delta \mathrm{t}$

$=1 	imes 10 	imes 4$

$=40 \mathrm{Ns}$

Range of a bob of mass $1\, kg$ is $80\,m$ while it attains maximum height $20\,m$. Its change in momentum in complete motion ............ $N-s$

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