Rakesh sets out to cycle from Delhi to Mathur | vedclass

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Question

(A) Let Rakesh's speed be $v_1$ and Suresh's speed be $v_2$.Let the time taken by them after meeting be $T_1 = 9 \, 	ext{hours}$ and $T_2 = 16 \, 	e

Vedclass · Accepted Answer

$12 \, 	ext{km/h}$

Vedclass · Answer

(A) Let Rakesh's speed be $v_1$ and Suresh's speed be $v_2$.Let the time taken by them after meeting be $T_1 = 9 \, 	ext{hours}$ and $T_2 = 16 \, 	ext{hours}$ respectively.The formula for the ratio of speeds when two people meet and then complete their journeys in times $T_1$ and $T_2$ is given by $\frac{v_1}{v_2} = \sqrt{\frac{T_2}{T_1}}$.Substituting the given values: $\frac{16}{v_2} = \sqrt{\frac{16}{9}}$.$\frac{16}{v_2} = \frac{4}{3}$.$4 	imes v_2 = 16 	imes 3$.$4 	imes v_2 = 48$.$v_2 = 12 \, 	ext{km/h}$.Thus,Suresh's speed is $12 \, 	ext{km/h}$.

Rakesh sets out to cycle from Delhi to Mathura and at the same time Suresh starts from Mathura to Delhi. After passing each other,they complete their journeys in $9$ and $16 \, \text{hours}$,respectively. At what speed does Suresh cycle if Rakesh cycles at $16 \, \text{km/h}$?

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