Prussian blue is formed when

  • A
    Ferrous sulphate reacts with $FeCl_3$
  • B
    Ferric sulphate reacts with $K_4[Fe(CN)_6]$
  • C
    Ferrous ammonium sulphate reacts with $FeCl_3$
  • D
    Ammonium sulphate reacts with $FeCl_3$

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