The product (C) of the following reaction is: | vedclass

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(C) Step $1$: Reaction of $1-chloro-4-nitrobenzene$ with $aq. NH_3$ undergoes nucleophilic aromatic substitution $(S_NAr)$ to form $4-nitroaniline$ as

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$1,3-$dibromo$-5-$nitrobenzene

Vedclass · Answer

(C) Step $1$: Reaction of $1-chloro-4-nitrobenzene$ with $aq. NH_3$ undergoes nucleophilic aromatic substitution $(S_NAr)$ to form $4-nitroaniline$ as product $(A)$.Step $2$: $4-nitroaniline$ reacts with $Br_2/H_2O$ to form $2,6-dibromo-4-nitroaniline$ as product $(B)$ due to the strong activating effect of the $-NH_2$ group.Step $3$: The reaction of $(B)$ with $(i) NaNO_2 + HCl$ followed by $(ii) H_3PO_2$ involves diazotization of the $-NH_2$ group followed by deamination (reduction of the diazonium salt to a hydrogen atom).Thus,the final product $(C)$ is $1,3-dibromo-5-nitrobenzene$.

List-$I$	List-$II$
$a$. Gabriel synthesis	$i$. Benzaldehyde
$b$. Kolbe synthesis	$ii$. Ethers
$c$. Williamson synthesis	$iii$. Primary amines
$d$. Etard reaction	$iv$. Salicylic acid

The product $(C)$ of the following reaction is:

Similar Questions

Match List-$I$ with List-$II$ :

List-$I$ List-$II$

$a$. Gabriel synthesis $i$. Benzaldehyde

$b$. Kolbe synthesis $ii$. Ethers

$c$. Williamson synthesis $iii$. Primary amines

$d$. Etard reaction $iv$. Salicylic acid

Choose the correct answer from the options given below :

The end product $C$ of the following reaction is $C_2H_5NH_2$ $\xrightarrow{HNO_2} A$ $\xrightarrow{PCl_5} B$ $\xrightarrow{NH_3 (alc.)} C$

$(A)$ $\xrightarrow{KOBr} (B)$ $\xrightarrow[KOH]{CHCl_3} (C)$ $\xrightarrow{LiAlH_4} \text{Structure of } (C) \text{ is}$

The product $(A)$ of the given reaction is:

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