The product $(C)$ of the above reaction is:

  • A
    $CH_3-C(=O)-CH_2-CH_2-C(OH)(CH_3)_2$
  • B
    $CH_3-C(OH)(CH_3)-CH_2-CH_2-C(OH)(CH_3)_2$
  • C
    $CH_3-C(=O)-CH_2-CH_2-C(=O)-CH_3$
  • D
    $CH_3-CH_2-C(=O)-CH_2-CH_2-CH_3$

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Similar Questions

Identify compounds $X$ and $Y$ in the following reaction: $CH_3COOH + X$ $\xrightarrow{H^+} Y$ $\xrightarrow{H_2, Pd} 2C_2H_5OH$

Compound $A$ was prepared by oxidation of compound $B$ with alkaline $KMnO_4$. Compound $A$ on reduction with lithium aluminium hydride $(LiAlH_4)$ gets converted back to compound $B$. When compound $A$ is heated with compound $B$ in the presence of $H_2SO_4$,it produces a fruity smell of compound $C$. To which family do the compounds $A$,$B$,and $C$ belong?

The final product $(III)$ obtained in the reaction sequence is:
$CH_3-CH_2-COOH$ $\xrightarrow{PCl_3} I$ $\xrightarrow{C_6H_6/AlCl_3} II$ $\xrightarrow{NH_2-NH_2/\text{base/heat}} III$

Select the reaction with an incorrect name.

In the following reaction sequence,the compound $J$ is an intermediate.
$I$ $\xrightarrow{(CH_3CO)_2O / CH_3COONa} J$ $\xrightarrow[(ii) \text{ anhyd. } AlCl_3]{(i) H_2, Pd/C, (ii) SOCl_2} K$
$J \left( C_9H_8O_2 \right)$ gives effervescence on treatment with $NaHCO_3$ and positive Baeyer's test.
$1.$ The compound $K$ is
$2.$ The compound $I$ is
Give the answer for question $1$ and $2.$

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