In the following reaction sequence,the compound $J$ is an intermediate.
$I$ $\xrightarrow{(CH_3CO)_2O / CH_3COONa} J$ $\xrightarrow[(ii) \text{ anhyd. } AlCl_3]{(i) H_2, Pd/C, (ii) SOCl_2} K$
$J \left( C_9H_8O_2 \right)$ gives effervescence on treatment with $NaHCO_3$ and positive Baeyer's test.
$1.$ The compound $K$ is
$2.$ The compound $I$ is
Give the answer for question $1$ and $2.$
$I$ $\xrightarrow{(CH_3CO)_2O / CH_3COONa} J$ $\xrightarrow[(ii) \text{ anhyd. } AlCl_3]{(i) H_2, Pd/C, (ii) SOCl_2} K$
$J \left( C_9H_8O_2 \right)$ gives effervescence on treatment with $NaHCO_3$ and positive Baeyer's test.
$1.$ The compound $K$ is
$2.$ The compound $I$ is
Give the answer for question $1$ and $2.$
- A$(B, D)$
- B$(B, C)$
- C$(C, A)$
- D$(A, D)$
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Write the chemical reactions for the following conversions:
$1.$ $1$-Bromopropane to Propan-$1$-ol and Propan-$2$-ol
$2.$ Ethanoic acid to Methanol
$1.$ $1$-Bromopropane to Propan-$1$-ol and Propan-$2$-ol
$2.$ Ethanoic acid to Methanol
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View SolutionWhat is the product of the following reaction?
Hydrolysis of an ester gives a carboxylic acid,which upon Kolbe's electrolysis yields ethane. Identify the ester.
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View SolutionConsidering the reaction sequence given below,the correct statement$(s)$ is(are):
$A$. $P$ can be reduced to a primary alcohol using $NaBH_4$.
$B$. Treating $P$ with conc. $NH_4OH$ solution followed by acidification gives $Q$.
$C$. Treating $Q$ with a solution of $NaNO_2$ in aq. $HCl$ liberates $N_2$.
$D$. $P$ is more acidic than $CH_3CH_2COOH$.
$A$. $P$ can be reduced to a primary alcohol using $NaBH_4$.
$B$. Treating $P$ with conc. $NH_4OH$ solution followed by acidification gives $Q$.
$C$. Treating $Q$ with a solution of $NaNO_2$ in aq. $HCl$ liberates $N_2$.
$D$. $P$ is more acidic than $CH_3CH_2COOH$.
What are $\underline{A}, \underline{B}, \underline{C}$ in the following reactions?
$(I)$ $(CH_3 CO_2)_2 Ca \stackrel{\Delta}{\longrightarrow} \underline{A}$
$(II)$ $CH_3 CO_2 H \underset{\text{Red P}}{\stackrel{HI}{\longrightarrow}} \underline{B}$
$(III)$ $2 CH_3 CO_2 H \stackrel{P_4 O_{10}}{\longrightarrow} \underline{C}$
$\underline{A} \quad \underline{B} \quad \underline{C}$
$(I)$ $(CH_3 CO_2)_2 Ca \stackrel{\Delta}{\longrightarrow} \underline{A}$
$(II)$ $CH_3 CO_2 H \underset{\text{Red P}}{\stackrel{HI}{\longrightarrow}} \underline{B}$
$(III)$ $2 CH_3 CO_2 H \stackrel{P_4 O_{10}}{\longrightarrow} \underline{C}$
$\underline{A} \quad \underline{B} \quad \underline{C}$
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