(C) The transformer equation is given by $\frac{V_1}{V_2} = \frac{N_1}{N_2}$.Given $V_1 = 230 \ V$ and $\frac{N_1}{N_2} = 10$,we have $\frac{230}{V_2}

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(C) The transformer equation is given by $\frac{V_1}{V_2} = \frac{N_1}{N_2}$.Given $V_1 = 230 \ V$ and $\frac{N_1}{N_2} = 10$,we have $\frac{230}{V_2} = 10$.Thus,the secondary voltage is $V_2 = \frac{230}{10} = 23 \ V$.The power consumed by the load resistance $R = 46 \ \Omega$ is given by $P = \frac{V_2^2}{R}$.Substituting the values,$P = \frac{23 \times 23}{46} = \frac{529}{46} = 11.5 \ W$.

Class 12 Physics Electromagnetic Induction Transformer

Difficult

Primary side of a transformer is connected to $230 \ V, 50 \ Hz$ supply. The turns ratio of primary to secondary winding is $10:1$. The load resistance connected to the secondary side is $46 \ \Omega$. The power consumed in it is: (in $W$)

JEE MAIN 2024 All JEE MAIN

A
$12.5$
B
$10.0$
C
$11.5$
D
$12.0$

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Electromagnetic Induction

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Transformer

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In a transformer,$220 \ V$ $AC$ voltage is increased to $2200 \ V$. If the number of turns in the secondary coil is $2000$,then the number of turns in the primary coil will be:

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$A$ transformer has an efficiency of $80 \%$ and works at $10 \ V$ and $4 \ kW$. If the secondary voltage is $240 \ V$, then the current in the secondary coil is: (in $A$)

DifficultJEE MAIN 2024

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$A$ step-up transformer has a turns ratio of $10:1$. $A$ cell of $e.m.f. = 5 \, V$ is connected to the primary coil. What is the secondary voltage developed?

Easy

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In a step-up transformer,the turn ratio is $8:1$. $A$ $60\,Hz, 120\,V$ input is connected to its primary coil. The load resistance in the secondary coil is $10^4\,\Omega$. Find the current in the secondary coil.

Medium

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Primary side of a transformer is connected to $230 \ V, 50 \ Hz$ supply. The turns ratio of primary to secondary winding is $10:1$. The load resistance connected to the secondary side is $46 \ \Omega$. The power consumed in it is: (in $W$)

Similar Questions

In a transformer,$220 \ V$ $AC$ voltage is increased to $2200 \ V$. If the number of turns in the secondary coil is $2000$,then the number of turns in the primary coil will be:

$A$ transformer with efficiency $80\%$ works at $4\, kW$ and $100\, V$. If the secondary voltage is $200\, V$, then the primary and secondary currents are respectively:

$A$ transformer has an efficiency of $80 \%$ and works at $10 \ V$ and $4 \ kW$. If the secondary voltage is $240 \ V$, then the current in the secondary coil is: (in $A$)

$A$ step-up transformer has a turns ratio of $10:1$. $A$ cell of $e.m.f. = 5 \, V$ is connected to the primary coil. What is the secondary voltage developed?

In a step-up transformer,the turn ratio is $8:1$. $A$ $60\,Hz, 120\,V$ input is connected to its primary coil. The load resistance in the secondary coil is $10^4\,\Omega$. Find the current in the secondary coil.

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