In a step-up transformer,the turn ratio is 8: | vedclass

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(D) Given,the turn ratio $\frac{N_s}{N_p} = 8:1 = 8$.Input voltage $V_p = 120\,V$.For an ideal transformer,the ratio of voltages is equal to the turn

Vedclass · Accepted Answer

$96\,mA$

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(D) Given,the turn ratio $\frac{N_s}{N_p} = 8:1 = 8$.Input voltage $V_p = 120\,V$.For an ideal transformer,the ratio of voltages is equal to the turn ratio:$\frac{V_s}{V_p} = \frac{N_s}{N_p} = 8$.Therefore,the secondary voltage $V_s = 8 	imes V_p = 8 	imes 120\,V = 960\,V$.The load resistance $R_s = 10^4\,\Omega$.Using Ohm's law,the current in the secondary coil $I_s = \frac{V_s}{R_s}$.$I_s = \frac{960}{10^4} = 960 	imes 10^{-4} = 96 	imes 10^{-3}\,A$.$I_s = 96\,mA$.

In a step-up transformer,the turn ratio is $8:1$. $A$ $60\,Hz, 120\,V$ input is connected to its primary coil. The load resistance in the secondary coil is $10^4\,\Omega$. Find the current in the secondary coil.

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