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(A) The detector receives both direct and reflected waves,forming a standing wave pattern.The distance between two consecutive maxima in a standing wa

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$1.5 	imes 10^{10}\, Hz$

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(A) The detector receives both direct and reflected waves,forming a standing wave pattern.The distance between two consecutive maxima in a standing wave is $\lambda / 2$.For $14$ successive maxima,there are $13$ intervals of $\lambda / 2$.Given that the distance traveled is $0.13\, m$,we have:$13 	imes \frac{\lambda}{2} = 0.13\, m$$\frac{\lambda}{2} = 0.01\, m$$\lambda = 0.02\, m$Using the relation $c = f \lambda$,where $c = 3 	imes 10^8\, m/s$:$f = \frac{c}{\lambda} = \frac{3 	imes 10^8}{0.02} = 1.5 	imes 10^{10}\, Hz$.

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