Phenol reacts with CCl_4 in the presence of a | vedclass

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(B) The reaction of phenol with $CCl_4$ in the presence of an aqueous alkali (like $KOH$) is known as the Reimer-Tiemann reaction (specifically the va

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Salicylic acid

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(B) The reaction of phenol with $CCl_4$ in the presence of an aqueous alkali (like $KOH$) is known as the Reimer-Tiemann reaction (specifically the variant using $CCl_4$).This reaction proceeds as follows:$C_6H_5OH + CCl_4 + 4KOH \rightarrow C_6H_4(OH)(COOK) + 4KCl + 2H_2O$The intermediate product formed is the potassium salt of salicylic acid.Upon subsequent acidic hydrolysis,this salt is converted into salicylic acid $(2-hydroxybenzoic \ acid)$.

Phenol reacts with $CCl_4$ in the presence of aqueous alkali and forms a product which on hydrolysis gives:

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