A person whose father is colourblind marries | vedclass

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(D) $1$. The man's father is colourblind. Since colourblindness is an $X$-linked recessive trait,the man receives his $Y$ chromosome from his father a

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Some sons normal and some colour blind

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(D) $1$. The man's father is colourblind. Since colourblindness is an $X$-linked recessive trait,the man receives his $Y$ chromosome from his father and his $X$ chromosome from his mother. Therefore,the man is genetically normal $(XY)$.$2$. The lady's mother is the daughter of a colourblind man. This means the lady's mother is a carrier $(X^CX)$. The lady herself is the daughter of this carrier mother. There is a $50\%$ probability that the lady is a carrier $(X^CX)$ and a $50\%$ probability that she is normal $(XX)$. Assuming the standard pedigree problem context,we consider the lady as a carrier $(X^CX)$.$3$. The cross between a normal man $(XY)$ and a carrier lady $(X^CX)$ results in the following genotypes for their children: $XX$ (normal daughter),$X^CX$ (carrier daughter),$XY$ (normal son),and $X^CY$ (colourblind son).$4$. Thus,the sons will be some normal and some colourblind.

$A$ person whose father is colourblind marries a lady whose mother is the daughter of a colourblind man. Their children will be:

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