Pair of species among the following having sa | vedclass

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(C) To determine the bond order and magnetic nature,we use the Molecular Orbital Theory $(MOT)$ configuration:SpeciesBond Order and Magnetic Nature$O_

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$O_{2}^{+}, N_{2}^{-}$

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(C) To determine the bond order and magnetic nature,we use the Molecular Orbital Theory $(MOT)$ configuration:SpeciesBond Order and Magnetic Nature$O_{2}^{+}$ ($15$ electrons)$2.5$,Paramagnetic$O_{2}^{-}$ ($17$ electrons)$1.5$,Paramagnetic$N_{2}^{+}$ ($13$ electrons)$2.5$,Paramagnetic$N_{2}^{-}$ ($15$ electrons)$2.5$,Paramagnetic$N_{2}^{2-}$ ($16$ electrons)$2.0$,Paramagnetic$N_{2}$ ($14$ electrons)$3.0$,DiamagneticComparing the options:$O_{2}^{+}$ has a bond order of $2.5$ and is paramagnetic.$N_{2}^{-}$ has a bond order of $2.5$ and is paramagnetic.Therefore,the pair $(O_{2}^{+}, N_{2}^{-})$ has the same bond order and magnetic character.

Pair of species among the following having same bond order as well as paramagnetic character will be -

Similar Questions

The number of species from the following which are paramagnetic and with bond order equal to $1$ is:
$H_2, He_2^{+}, O_2^{+}, N_2^{2-}, O_2^{2-}, F_2, Ne_2^{+}, B_2$

Match the following molecules/ions in List-$I$ with their respective bond orders in List-$II$:
| List-$I$ (Molecules/ions) | List-$II$ (Bond order) |
| :--- | :--- |
| $A. N_2^+$ | $I. 1.0$ |
| $B. CO$ | $II. 1.5$ |
| $C. O_2$ | $III. 2.0$ |
| $D. O_2^-$ | $IV. 2.5$ |
| | $V. 3.0$ |

Which of the following species is paramagnetic?

What is $LCAO$? Explain.

Among $KO_2$,$KAlO_2$,$CaO_2$ and $NO_2^+$,unpaired electron is present in

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