The pair of equations ax - y = 5 and 4x - 2y | vedclass

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(A) For a pair of linear equations $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$ to have infinitely many solutions,the condition is $\frac{a_1}{

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$2$

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(A) For a pair of linear equations $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$ to have infinitely many solutions,the condition is $\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}$.Given equations are $ax - y - 5 = 0$ and $4x - 2y - 10 = 0$.Here,$a_1 = a, b_1 = -1, c_1 = -5$ and $a_2 = 4, b_2 = -2, c_2 = -10$.Applying the condition: $\frac{a}{4} = \frac{-1}{-2} = \frac{-5}{-10}$.This simplifies to $\frac{a}{4} = \frac{1}{2} = \frac{1}{2}$.Therefore,$\frac{a}{4} = \frac{1}{2}$,which gives $a = \frac{4}{2} = 2$.

The pair of equations $ax - y = 5$ and $4x - 2y = 10$ has an infinite number of solutions. Then $a = \ldots$

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