Out of the following bulbs rated 40 W, 220 | vedclass

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(A) The resistance of a bulb is given by the formula $R = \frac{V^2}{P}$.Since all bulbs have the same voltage rating $(V = 220 \ V)$,the resistance i

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$40 \ W$ bulb

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(A) The resistance of a bulb is given by the formula $R = \frac{V^2}{P}$.Since all bulbs have the same voltage rating $(V = 220 \ V)$,the resistance is inversely proportional to the power $(R \propto \frac{1}{P})$.Therefore,the $40 \ W$ bulb has the highest resistance.When bulbs are connected in series,the same current $(I)$ flows through each bulb.The power dissipated (brightness) in each bulb is given by $P_{actual} = I^2 R$.Since $I$ is constant for all bulbs in series,the brightness is directly proportional to the resistance $(P_{actual} \propto R)$.Because the $40 \ W$ bulb has the highest resistance,it will dissipate the most power and glow the brightest.

Out of the following bulbs rated $40 \ W, 220 \ V$,$60 \ W, 220 \ V$,and $100 \ W, 220 \ V$,which one will glow the brightest when connected in series to a supply of $220 \ V$?

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