A bulb is rated at $5.0\, V , 100 \,mA$. Calculate its

$(i)$ power and $(ii)$ resistance.

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Given, $\quad V =5.0 V$

$I=100 mA =100 \times 10^{-3} A =0.1 A$

$P = VI =5.0 \times 0.1=0.5 W$

Also, $R =\frac{ V }{ I }=\frac{5.0}{0.1}$

$=50 \Omega$

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