Out of 30 consecutive numbers,2 are chosen at | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The total number of ways to choose $2$ integers from $30$ consecutive integers is given by $^{30}C_2 = \frac{30 	imes 29}{2} = 435$.For the sum o

Vedclass · Accepted Answer

$\frac{15}{29}$

Vedclass · Answer

(C) The total number of ways to choose $2$ integers from $30$ consecutive integers is given by $^{30}C_2 = \frac{30 	imes 29}{2} = 435$.For the sum of two numbers to be odd,one number must be even and the other must be odd.In $30$ consecutive integers,there are $15$ even numbers and $15$ odd numbers.The number of ways to choose one even number and one odd number is $^{15}C_1 	imes ^{15}C_1 = 15 	imes 15 = 225$.The required probability is $\frac{	ext{Favourable outcomes}}{	ext{Total outcomes}} = \frac{225}{435}$.Dividing both numerator and denominator by $15$,we get $\frac{225 \div 15}{435 \div 15} = \frac{15}{29}$.

Out of $30$ consecutive numbers,$2$ are chosen at random. The probability that their sum is odd,is

Similar Questions

Find the chance of throwing $6$ at least once in six throws with a single die.

For any event $A$,which of the following is true?

$A$ box contains $10$ good articles and $6$ with defects. One article is chosen at random. What is the probability that it is either good or has a defect?

Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?

$A$ jar contains $3$ red marbles,$7$ green marbles and $10$ white marbles. If a marble is drawn from the jar at random,what is the probability that this marble is white?

Vedclass Test Series

Exam Paper Generator

Online Exam Module