The orthocentre of the triangle formed by the | vedclass

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(A) The given lines are $x + y = 1$,$x = 0$,and $y = 0$.These lines represent the sides of a triangle.The vertices of the triangle are the points of i

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$(0,0)$

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(A) The given lines are $x + y = 1$,$x = 0$,and $y = 0$.These lines represent the sides of a triangle.The vertices of the triangle are the points of intersection of these lines:$1$. Intersection of $x = 0$ and $y = 0$ is $(0, 0)$.$2$. Intersection of $x = 0$ and $x + y = 1$ is $(0, 1)$.$3$. Intersection of $y = 0$ and $x + y = 1$ is $(1, 0)$.The triangle has vertices at $(0, 0)$,$(0, 1)$,and $(1, 0)$.Since the sides $x = 0$ (the $y$-axis) and $y = 0$ (the $x$-axis) are perpendicular,this is a right-angled triangle with the right angle at the vertex $(0, 0)$.The orthocentre of a right-angled triangle is the vertex where the right angle is located.Therefore,the orthocentre is $(0, 0)$.

The orthocentre of the triangle formed by the lines $x + y = 1$ and $xy = 0$ is

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