Optical activity of an enantiomeric mixture i | vedclass

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Question

(D) The optical purity of an enantiomeric mixture is calculated using the formula: $	ext{Optical Purity} = \frac{	ext{observed rotation of mixture}}

Vedclass · Accepted Answer

$42$

Vedclass · Answer

(D) The optical purity of an enantiomeric mixture is calculated using the formula: $	ext{Optical Purity} = \frac{	ext{observed rotation of mixture}}{	ext{specific rotation of pure enantiomer}} 	imes 100$. Given: $	ext{Observed rotation} = +12.6^{\circ}$ and $	ext{Specific rotation} = +30^{\circ}$. Substituting the values: $	ext{Optical Purity} = \frac{12.6}{30} 	imes 100 = 0.42 	imes 100 = 42\%$. Thus,the optical purity is $42\%$.

Optical activity of an enantiomeric mixture is $+12.6^{\circ}$ and the specific rotation of the $(+)$ isomer is $+30^{\circ}$. The optical purity is $......... \%$.

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