One ticket is drawn at random out of 30 ticke | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The total number of tickets is $30$,so the sample space $S = \{1, 2, 3, \ldots, 30\}$ and $n(S) = 30$.Let $A$ be the event of drawing a ticket wit

Vedclass · Accepted Answer

$\frac{1}{3}$

Vedclass · Answer

(B) The total number of tickets is $30$,so the sample space $S = \{1, 2, 3, \ldots, 30\}$ and $n(S) = 30$.Let $A$ be the event of drawing a ticket with a number that is a multiple of $5$.$A = \{5, 10, 15, 20, 25, 30\}$,so $n(A) = 6$.Let $B$ be the event of drawing a ticket with a number that is a multiple of $7$.$B = \{7, 14, 21, 28\}$,so $n(B) = 4$.Since $A$ and $B$ are mutually exclusive events (there are no common multiples of $5$ and $7$ up to $30$),the probability of $A$ or $B$ is given by $P(A \cup B) = P(A) + P(B)$.$P(A) = \frac{n(A)}{n(S)} = \frac{6}{30}$.$P(B) = \frac{n(B)}{n(S)} = \frac{4}{30}$.Therefore,$P(A \cup B) = \frac{6}{30} + \frac{4}{30} = \frac{10}{30} = \frac{1}{3}$.

One ticket is drawn at random out of $30$ tickets numbered from $1$ to $30.$ Find the probability that the number on the ticket is a multiple of $5$ or $7.$

Similar Questions

Find the probability that in a random arrangement of letters of the word $'UNIVERSITY'$, two $I$s do not come together.

$A$ bag contains $5$ white,$7$ black,and $4$ red balls. Three balls are drawn from the bag at random. The probability that all the three balls are white is:

Two dice are tossed. The probability that the total score is a prime number is

$2$ dice are thrown. Find the probability of getting a multiple of $3$ as the sum.

Three letters are to be sent to different persons,and addresses on the three envelopes are also written. Without looking at the addresses,the probability that all the letters go into the right envelope is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module