One root of the given equation 2x^5 - 14x^4 + | vedclass

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(C) To find the root,we substitute the given options into the equation $f(x) = 2x^5 - 14x^4 + 31x^3 - 64x^2 + 19x + 130 = 0$.For $x = 5$:$f(5) = 2(5)^

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$5$

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(C) To find the root,we substitute the given options into the equation $f(x) = 2x^5 - 14x^4 + 31x^3 - 64x^2 + 19x + 130 = 0$.For $x = 5$:$f(5) = 2(5)^5 - 14(5)^4 + 31(5)^3 - 64(5)^2 + 19(5) + 130$$f(5) = 2(3125) - 14(625) + 31(125) - 64(25) + 95 + 130$$f(5) = 6250 - 8750 + 3875 - 1600 + 95 + 130$$f(5) = (6250 + 3875 + 95 + 130) - (8750 + 1600)$$f(5) = 10350 - 10350 = 0$Since $f(5) = 0$,$x = 5$ is a root of the equation.

One root of the given equation $2x^5 - 14x^4 + 31x^3 - 64x^2 + 19x + 130 = 0$ is

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