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(A) The mass of ${ }_{1}^{2} H$ is $2.014102 \ u$. The mass of ${ }_{1}^{1} H$ is $1.007825 \ u$. The mass of ${ }_{2}^{3} He$ is $3.016029 \ u$. The

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$5.49$

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(A) The mass of ${ }_{1}^{2} H$ is $2.014102 \ u$. The mass of ${ }_{1}^{1} H$ is $1.007825 \ u$. The mass of ${ }_{2}^{3} He$ is $3.016029 \ u$. The mass defect $\Delta m = (m({ }_{1}^{2} H) + m({ }_{1}^{1} H)) - m({ }_{2}^{3} He)$. $\Delta m = (2.014102 + 1.007825) - 3.016029 = 3.021927 - 3.016029 = 0.005898 \ u$. The energy released $Q = \Delta m 	imes 931.5 \ MeV/u$. $Q = 0.005898 	imes 931.5 \approx 5.49 \ MeV$.

One of the fusion reactions in the sun is given by ${ }_{1}^{2} H+{ }_{1}^{1} H \rightarrow{ }_{2}^{3} He+\gamma+Q$. Calculate the energy $Q$ released in the reaction. (in $MeV$)

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