If the binding energy per nucleon for a deute | vedclass

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(C) The energy released $Q$ in a nuclear reaction is given by the difference between the total binding energy of the products and the total binding en

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$23.8$

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(C) The energy released $Q$ in a nuclear reaction is given by the difference between the total binding energy of the products and the total binding energy of the reactants.$Q = BE_{	ext{products}} - BE_{	ext{reactants}}$For the reaction $2 \, (_1H^2) ightarrow _2He^4 + Q$:Total binding energy of reactants = $2 	imes (2 	imes 1.112 \, MeV) = 4.448 \, MeV$.Total binding energy of products = $1 	imes (4 	imes 7.07 \, MeV) = 28.28 \, MeV$.$Q = 28.28 \, MeV - 4.448 \, MeV = 23.832 \, MeV$.Rounding to the nearest provided option,$Q \approx 23.8 \, MeV$.

If the binding energy per nucleon for a deuteron is $1.112 \, MeV$ and for an $\alpha$-particle is $7.07 \, MeV$,then for the reaction $2 \, (_1H^2) \rightarrow _2He^4 + Q$,the value of $Q$ is .......... $MeV$.

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