One face of a prism with a refracting angle o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given: Refracting angle $A = 30^{\circ}$,angle of incidence $i_{1} = 45^{\circ}$.Since the ray retraces its path after reflection from the silvere

Vedclass · Accepted Answer

$\sqrt{2}$

Vedclass · Answer

(D) Given: Refracting angle $A = 30^{\circ}$,angle of incidence $i_{1} = 45^{\circ}$.Since the ray retraces its path after reflection from the silvered face,the ray must strike the silvered face normally. Therefore,the angle of refraction at the second face is $r_{2} = 0^{\circ}$.Using the relation $r_{1} + r_{2} = A$,we get $r_{1} + 0^{\circ} = 30^{\circ}$,so $r_{1} = 30^{\circ}$.Applying Snell's Law at the first face: $\mu = \frac{\sin i_{1}}{\sin r_{1}}$.Substituting the values: $\mu = \frac{\sin 45^{\circ}}{\sin 30^{\circ}} = \frac{1/\sqrt{2}}{1/2} = \frac{2}{\sqrt{2}} = \sqrt{2}$.Thus,the refractive index of the prism is $\sqrt{2}$.

One face of a prism with a refracting angle of $30^{\circ}$ is coated with silver. $A$ ray incident on the other face at an angle of $45^{\circ}$ is refracted,reflected from the silver-coated face,and retraces its path. The refractive index of the prism is:

Similar Questions

$A$ prism of refractive index $\mu$ and angle of prism $A$ is placed in the position of minimum angle of deviation. If the minimum angle of deviation is also $A$, then the value of $A$ in terms of refractive index $\mu$ is ..... .

Find the value of the angle of emergence for an emergent ray from the prism in the figure given below. (Refractive index of the material of the prism is $\sqrt{3}$ and the refractive index of air is $1$) (in $^\circ$)

The angle of deviation $(\delta)$ vs angle of incidence $(i)$ is plotted for a prism. Pick the correct statement:-

Two thin prisms of flint glass, with refracting angles of $6^o$ and $8^o$ respectively, possess dispersive powers in the ratio

The exit surface of a prism with refractive index $n$ is coated with a material having refractive index $\frac{n}{2}$. When this prism is set for minimum angle of deviation,it exactly meets the condition of the critical angle. The prism angle is . . . . . . (in $^{\circ}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module