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(C) Total number of cards $n(S) = 52$. Let $A$ be the event that the card is a king and $B$ be the event that the card is a diamond. Number of kings $

Vedclass · Accepted Answer

$\frac{4}{13}$

Vedclass · Answer

(C) Total number of cards $n(S) = 52$. Let $A$ be the event that the card is a king and $B$ be the event that the card is a diamond. Number of kings $n(A) = 4$. Number of diamonds $n(B) = 13$. The king of diamonds is common to both,so $n(A \cap B) = 1$. Using the addition theorem of probability: $P(A \cup B) = P(A) + P(B) - P(A \cap B)$. $P(A \cup B) = \frac{4}{52} + \frac{13}{52} - \frac{1}{52} = \frac{16}{52}$. Simplifying the fraction: $\frac{16}{52} = \frac{4}{13}$.

One card is drawn from a pack of $52$ cards. The probability that it is a king or a diamond is

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